1 5x^2y^3
2 sqrt(2^7a^6b^9)= 2^5a^4b^7=32a^4b^7
3 - 2mn^11
4 sqrt^4(-162)r
По формуле n-ного члена арифметической прогрессии:
log²(1/2) x + 3log(1/2) x + 2 = 0
x > 0
log(1/2) x = t
t² + 3t + 2 = 0
D = b² - 4ac = 9 - 8 = 1
t12 = (-3 +- 1)/2 = -1 -2
t1 = -1
log(1/2) x = -1
x = (1/2)^(-1)
x = 2
t2 = -2
log(1/2) x = -2
x = (1/2)^(-2)
x = 4
ответ 2 и 4