Solve for x over the real numbers:
x^2+4 = 6-x
Subtract 6-x from both sides:
x^2+x-2 = 0
The left hand side factors into a product with two terms:
(x-1) (x+2) = 0
Split into two equations:
x-1 = 0 or x+2 = 0
Add 1 to both sides:
x = 1 or x+2 = 0
Subtract 2 from both sides:
Answer: |
| x = 1 or x = -2
Удачи!
<span>(3a-2b)^3+8b^3=</span>36*a*b^2-54*a^2*b+27*a^3-8b^3+8b^3=9*a*(4*b^2-6*a*b+3*a^2)