Question

СРОЧНОООООО! Решить уравнение: 3,24-х^2=0; 2у^2-2,42=0.

Answer 1

$3,24-x^2=0 \\ x^2-3.24=0 \\ x^{2} -1.8 ^2=0 \\ (x-1.8)(x+1.8)=0 \\ x-1.8=0 \\ x_1=1.8 \\ x+1.8=0 \\ x_2=-1.8$

$2y^2-2,42=0 \\ 2( y^{2} -1.21)=0 \\ y ^{2}-1.1^2=0 \\ (y-1.1)(y+1.1)=0 \\ y-1.1=0 \\ y_1=1.1 \\ y+1.1=0 \\ y_2=-1.1$