![\sqrt{5x^2+x} \geq 3x-1](https://tex.z-dn.net/?f=+%5Csqrt%7B5x%5E2%2Bx%7D++%5Cgeq+3x-1)
ОДЗ:
![5x^2+x \geq 0 \\ x(5x+1) \geq 0](https://tex.z-dn.net/?f=5x%5E2%2Bx+%5Cgeq+0+%5C%5C+x%285x%2B1%29+%5Cgeq+0)
a>0 ⇒ x∈(-∞;-1/5]U[0;+∞)
![5x^2+x \geq 9x^2-6x+1 \\ 4x^2-7x+1 \leq 0 \\ \\ 4x^2-7x+1=0 \\ D=49-16=33 \\ x_1= \dfrac{7- \sqrt{33} }{8} \\ x_2= \dfrac{7+ \sqrt{33} }{8}](https://tex.z-dn.net/?f=5x%5E2%2Bx+%5Cgeq+9x%5E2-6x%2B1+%5C%5C+4x%5E2-7x%2B1+%5Cleq+0+%5C%5C++%5C%5C+4x%5E2-7x%2B1%3D0+%5C%5C+D%3D49-16%3D33+%5C%5C+x_1%3D+%5Cdfrac%7B7-+%5Csqrt%7B33%7D+%7D%7B8%7D++%5C%5C+x_2%3D+%5Cdfrac%7B7%2B+%5Csqrt%7B33%7D+%7D%7B8%7D+)
Т.к.
![\sqrt{5x^2+x} = 3x-1](https://tex.z-dn.net/?f=%5Csqrt%7B5x%5E2%2Bx%7D+%3D+3x-1)
и
![\sqrt{5x^2+x} \geq 0](https://tex.z-dn.net/?f=+%5Csqrt%7B5x%5E2%2Bx%7D+%5Cgeq+0+)
то
![3x-1 \geq 0 \\ x \geq \dfrac{1}{3}](https://tex.z-dn.net/?f=3x-1+%5Cgeq+0+%5C%5C+x+%5Cgeq++%5Cdfrac%7B1%7D%7B3%7D+)
значит x=7-√33/8 - не точка смены знака в решении неравенства
С учетом ОДЗ
x∈(-∞;-1/5]U[0;7+√33/8]
Ответ: x∈(-∞;-1/5]U[0;7+√33/8]
![\frac{2sin^2x-5sinx-3}{ \sqrt{x- \pi /6} } =0](https://tex.z-dn.net/?f=+%5Cfrac%7B2sin%5E2x-5sinx-3%7D%7B+%5Csqrt%7Bx-+%5Cpi+%2F6%7D+%7D+%3D0)
![\left \{ {{2sin^2x-5sinx-3=0} \atop {x- \pi /6\ \textgreater \ 0}} \right.](https://tex.z-dn.net/?f=+%5Cleft+%5C%7B+%7B%7B2sin%5E2x-5sinx-3%3D0%7D+%5Catop+%7Bx-+%5Cpi+%2F6%5C+%5Ctextgreater+%5C+0%7D%7D+%5Cright.+)
x>pi/6
2sin²x-5sinx-3=0
sinx=t |t|≤1
D=25+24=49
t=5-7/4=-1/2
t=5+7/4=3 посторонний корень
sinx=-1/2
х=-пи/6+2*пи*n n∈Z
x=-5pi/6+2*pi*n n∈Z
т.к. х>пи/6 то n∈N
Ответ
х=-пи/6+2*пи*n n∈N
x=-5pi/6+2*pi*n n∈N
ОДЗ :
x² - 2x - 8 > 0
(x - 4)(x + 2) > 0
+ - +
_____________₀__________₀___________
- 2 4
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x ∈ ( - ∞ , - 2) ∪ (4 ; + ∞)
![log_{\frac{1}{3} }(x^{2}-2x-8)+3>0\\\\log_{\frac{1}{3} }(x^{2}-2x-8)>-3\\\\x^{2}-2x-8<27\\\\x^{2}-2x-35<0\\\\x^{2}-2x-35=0\\\\D=(-2)^{2}-4*(-35)=4+140=144=12^{2}\\\\x_{1}=\frac{2+12}{2}=7\\\\x_{2}=\frac{2-12}{2} =-5](https://tex.z-dn.net/?f=log_%7B%5Cfrac%7B1%7D%7B3%7D+%7D%28x%5E%7B2%7D-2x-8%29%2B3%3E0%5C%5C%5C%5Clog_%7B%5Cfrac%7B1%7D%7B3%7D+%7D%28x%5E%7B2%7D-2x-8%29%3E-3%5C%5C%5C%5Cx%5E%7B2%7D-2x-8%3C27%5C%5C%5C%5Cx%5E%7B2%7D-2x-35%3C0%5C%5C%5C%5Cx%5E%7B2%7D-2x-35%3D0%5C%5C%5C%5CD%3D%28-2%29%5E%7B2%7D-4%2A%28-35%29%3D4%2B140%3D144%3D12%5E%7B2%7D%5C%5C%5C%5Cx_%7B1%7D%3D%5Cfrac%7B2%2B12%7D%7B2%7D%3D7%5C%5C%5C%5Cx_%7B2%7D%3D%5Cfrac%7B2-12%7D%7B2%7D+%3D-5)
+ - +
______________₀_____________₀_____________
- 5 7
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x ∈ (- 5 , 7)
С учётом ОДЗ окончательный ответ :
x ∈ (- 5 ; - 2) ∪ (4 , 7)