<span>у=1-х^2
a)y(0,5)=1-(0,5)^2=1-0,25=0,75
y(-2)=1-(-2)^2=1-4=-3
б)1-x^2=-8
x^2-9=0
(x-3)(x+3)=0
x-3=0 или x+3=0
x=3 x=-3
____________________
1-x^2=1
x^2=0
x=0
</span>
Y^-2y+1-y^2-6y+y-7=0
4y+8=0
4y=0-8
у= -8:4
у= -4
Запишем
A(ω)<=1.8Α(0)=Α(0)*ω(ρ)^2/mod[ω(ρ)^2-ω^2]
Решим относительно ω
1.8Α(0)=Α(0)*ω(ρ)^2/mod[ω(ρ)^2-ω^2]
1.8Α(0)*ω(ρ)^2-1.8Α(0)*ω^2=Α(0)*ω(ρ)^2
0.8Α(0)*ω(ρ)^2=1.8Α(0)*ω^2
4Α(0)*ω(ρ)^2=9Α(0)*ω^2--->ω=(2/3)*ω(ρ)=2*300/3=200 c^(-1)<ω(ρ)
ω=200 c^(-1)
3,3-√12<0 значит 3x-12≤0 3x≤12 x≤4