<span> f ’(x)=26x-7</span>
<span><span>f ’(0)= 26*0-7=-7</span></span>
<span> f ’(-1)=26*(-1)-7=-33</span>
<span><span>f’(0) + f’(-1)=-7+(-33)=-40</span></span>
(-2:0) (0:1) (2:2) вот координаты этих точек
15m²n-5mn=5mn(3m-1)
(3.5.m.m.n-5.m.n.1=5.m.n(3m-1)=5mn(3m-1)