Question

Помогитеее. Номер 2 и 3

Answer 1

2)a)(7m-n)(7m+n)/-3mn(7m-n)=-(7m+n)3mn
b)(9x-4)(9x+4)/(9x+4)^2=(9x-4)/(9x+4)
3)(x-4)^2-25=(x-4)^2-5^2=(x-4-5)(x-4+5)=(x-9)(x+1)=0
1)x-9=0          2) x+1=0
    x=9                  x=-1

Answer 2

№ 3
$(x-4)^{2} -25=0$
$x^{2} -2*4*х+16=0$
$x^{2} -8x-9=0$
$D= (-8)^{2} -4*1*(-9)=64+36=100$
$x_{1} = \frac{-(-8)+ \sqrt{100} }{2} =9$
$x_{1} = \frac{-(-8)- \sqrt{100} }{2} =-1$

№2
а)
$\frac{49 m^{2} - n^{2} }{3m n^{2} -21 m^{2}n } = \frac{(7m-n)*(7m+n)}{3mn(n-7m)} =-\frac{(7m-n)*(7m+n)}{3mn(7m-n)} =-\frac{7m+n}{3mn}$

б)
$\frac{81 x^{2} -16}{16+72x+81 x^{2} } = \frac{ (9x)^{2} - 4^{2} }{ 4^{2} +2*4*9x+ (9x)^{2} } = \frac{(9x-4)*(9[+4)}{(9x+4)^{2} } =\frac{9x-4}{9x+4 }$