A³-4a=a(a²-4)=a(a+2)(a-2)
ax²-ay²=a(x²-y²)=a(x+y)(x-y)
3a²-6ab+3b²=3(a²-2ab+b²)=3(a-b)(a-b)=3.(a-b)²
ax²+ax+a=a(x²+x+1)
x²+7x=0, x(x+7)=0, x1=0,x2=-7
x²-25=0, (x+5)(x-5)=0, x1=-5,x2=5
A-b=4 ⇒ b-a=-4
12/(-4)+16/(-4)²=-3+1=-2.
За теоремой виета
х1+х2=-b=-6
x1×x2=c=-27
x1=-9, x2=3
x^2 +6x -27 = (x +9)(x - 3), тоесть a=3.
Вот.