Y⁻²-(2y)⁻¹=0
1/y²-1/(2y)=0
(1*2-1*y)/(2y²)=0
2-y=0, 2y²≠0
y=2
ответ: у=2
<span>-х(3х-19)= -40
-3х</span>^2<span> - 19 = -40
-3х = -40 + 19 =-21
х = -21 : ( -3) =7</span>
Объяснение:
x=-1;0;1
y(-1)=3*(-1)+1/4=-3+1/4=-2 3/4
y(0)=3*(0)+1/4=1/4
y(1)=3*(1)+1/4=3 1/4