<span>Соs (3</span>π<span>/3) =cos(</span>π)=-1.<span>
Cos (3</span>π<span>/9) =cos (</span>π/3<span>)=0,5.</span>
Решение : /////////////////////////////
например: 1). x^2-4x+8 / (x-4) ; 2). x^3-3x-2 / (x+1)*(x-2). ^-это степень.
-5x+11x-6>0
6x> 6
x> 1
(1;+бесконечность)
4(x + 1,5) + 3(1 - x) = 10
4x + 6 + 3 - 3x = 10
x + 9 = 10
x = 1