Question

Алгебра 8 класс ...............​

Answer 1

Ответ:

Объяснение:

(2x-6)/15 - (4x-7)/10=(2(2x-6)-3(4x-7))/30=(4x-12-12x+21)/30=(9-8x)/30

(-3a+1)/6 -(3a+1)/9=(3(-3a+1)-2(3a+1))/18=(3-9a-6a-2)/18=(1-15a)/18

(1-b)/12 -(3b-4)/8=(2(1-b)-3(3b-4))/24=(2-2b-9b+12)/24=(14-11b)/24

(3t-a)/14 -(t+2a)/7=(3t-a-2(t+2a))/14=(3t-a-2t-4a)/14=(t-5a)/14

(2d+5)/15 -(3d-9)/10=(2(2d+5)-3(3d-9))/30=(4d+10-9d+27)/30=(37-5d)/30

(-6a+1)/6 +(-2a-3)/10=(5(-6a+1)+3(-2a-3))/30=(5-30a-6a-9)/30=(-36a-4)/30=2(-18a-2)/30=(-18a-2)/15

(2a-3)/a -(5d-1)/d=(d(2a-3)-a(5d-1))/(ad)=(2ad-3d-5ad+a)/(ad)=(a-3ad-3d)/(ad)

(7a-13)/a +(5b-11)/b=(b(7a-13)+a(5b-11))/(ab)=(7ab-13b+5ab-11a)/(ab)=(12ab-13b-11a)/(ab)

(4-5b)/b -(7-2a)/a=(a(4-5b)-b(7-2a))/(ab)=(4a-5ab-7b+2ab)/(ab)=(4a-3ab-7b)/(ab)

(8-3x)/x +(5+6t)/t=(t(8-3x)+x(5+6t))/(xt)=(8t-3xt+5x+6xt)/(xt)=(3xt+8t+5x)/(xt)