V(t)=x`(t)=6t²+t-1
v(1)=6+1-1=6
a(t)=v`(t)=12t+1
a(1)=12+1=13
6t²+t-1=0
D=1+24=25
t=(-1-5)/12=-1/2 не удов усл
t=(-1+5)/12=1/3
.............................................................................................
(4+x)(4-x)(x+4)вот так вроде
=интеграл х^(-2/3)dx=x^(-2/3+1)/(-2/3+1)=x^(1/3)/(1/3)=3x^(1/3)=3(27^(1/3)-8^(1/3)=3(3-2)=3