1) 1-cos(2t) 2)tant2(t)(-1+/sin2(t)
Ответ:
Объяснение:
<u>Sin x - cos x - cos 2x </u> = <u>sinx-cosx-cos²x+sin²x</u> =
sin x - cos x sin x - cos x sin x - cos x
<u>sinx-cosx-{(cosx-sinx)*((cosx+sinx)}</u> = <u>( sin x - cos x ) * (1+sinx+cosx) </u> =
sin x - cos x sin x - cos x
= 1+sinx+cosx
А1.
а)12с² - 6с = 6с(2с-1)
б)24у² - 8у = 8у(3y-1)
в)16х²у² - 4х² = 4х²(4у² - 1)
г) 12х^4 - 18х² + 6х = 6х(2х³ - 3х + 1)
А.2
a) x(b+c)+5b+5c = xb+xc+5b+5c = x(b+c)+6(b+c) = (x+6)(b+c)
б) 4x-4y+ax-ay = 4(x-y)+a(x-y) = (4+a)(x-y)
B1.
x^4-8x³+6x-48 = x³(x-8)+6(x-8) = (x³+6)(x-8)
B2.
am² - 2n - bm² + an + 2m² - bn = m²(a - b - 2) + n(-2 + a - b) = (m² + n)(a - b -2)
<span>a ( b + c - bc ) - b ( c + a - ac ) + c ( b - a )=ab+ac-abc-bc-ba+abc+bc-ac=0</span>