AB = AK + BK
AB = AK + ( AK - 4 )
36 = 2AK - 4
2AK = 40
AK = 20 ( cm )
BK = 20 - 4 = 16 ( cm )
-12x= -2,4-3,6
-12x= -6
x= -6/-12
x=0,5
<span>14а²+ 7ав 7а(2а+в) 7а
----------------- = -------------------- = ----------
</span><span> в²-4а² (в-2а)(в+2а) в-2а</span>
<span>X^5[X^2+4X+3) >=0
способом интервала, нули функции
x^5= 0 или </span>X^2+4X+3 = 0
x = 0
X^2+4X+3 = 0
D = 4^2 - 4*3 = 16 - 12 = 4
x1 = (-4 + 2)/2 = -2/2 = -1
x2 = (-4 -2)/2 = -6/2 = -3
_-_-3__+__-1__-__0__+__
х Э [-3;-1] v [0;+]
-2; -1;0;1;2;3;4;5;6 -
Ответ 9