(3;5) - сбоку; (-5;-3) - снизу
5x-3<2(x+3)
5x-3<2x+6
5x-2x<6+3
3x<9
x<9/3
x<3
x∈(-бесконечности; 3)
a) 2ab*(-3ac) = -2*3*a*a*b*c = -6a²bc
b) 4c*(-b)*b = -4*b*b*c = -4b²c
c) 0.25cd*(1/4)c = (1/4)*(1/4)c*c*d = (1/16)*c²d
<span>20<2*Х<24;
100<х²<144;
25<3х-5<31.</span>
<span> 2lg (x+4)=lg αx
(x+4)^=ax
x^+8x+16-ax=0
</span>