X^3 - 3x^2 - 4x + 12 = 0
x^2*(x-3)-4(x-3)=0
(x^2-4)*(x-3)=0
(x-2)*(x+2)(x-3)=0
x-2=0 x=2
x+2=0 x=-2
x-3=0 x=3
Otvet:
x1=2
x2=-2
x3=3
A) F(x) = x⁴/4 + 2x + C;
A(-1, 3)
3 = (-1)⁴/4 + 2 * (-1) + C = 0.25 - 2 + C;
3 = -1.75 + C => C = 3 + 1.75 = 4.75;
б) F(x) = x²/2 + 3x + C;
B(1, 2)
2 = 1/2 + 3*1 + C;
C = 2 - 3.5 = -1.5;
в) F(x) = 2x + x³/3 + C;
A(3, 1)
1 = 2*3 + 27/3 + C = 15 + C;
C = 1 - 15 = -14;
0.75(12x-4)-x-1/2x-1=0
9x-3-x-1/2x-1=0
8x-4/2x-1=0 домножим на знаменатель 2x-1
8x-4=0
8x=4/8
x=1/2 или 0,5