Ответ: 64i³ + 216j³ =(4i + 6j)(16i² - 24ij + 36j²)
X=π/3+y
(1+cos2x)/2+(1+cos2y)/2=-3/4
2+cos2x+cos2y=-3/2
cos2x+cos2y=-7/2
2cos(x+y)*cos(x-y)=-7/2
cos(x+y)cos(x-y)=-7/4
cos(2y+π/3)cosπ/3=-7/4
1/2cos(x+y)=-7/4
cos(x+y)=-7/2
нет решения,т.к. -7/2∉[-1;1]
2х+2=-3
2х=-3-2
2х=-5
х=-2,5