Question

2cos^2 2x-1=sin4x помогите решить. срочно!!!

Answer 1

2 cos^2 (2x) - 1 = sin4x 
cos4x - sin4x = 0   /: (-1)
sin4x - cos4x = 0  /:cos4x≠0
tg4x - 1 = 0 
tg4x = 1 
4x  = pi/4 + pik
x = pi/16 + pik/4 , k ∈Z