1)у'=2x-5+lnx
2)y=x³-5x²+x y'=3x²-10x+1
3) y=x³/x-5x²/x+1/x=x²-5x+1/x y'=2x-5+lnx
2x - ay + bz
a = 3c
b = 14c^3
x = 5c^3 + 2
y = 6c^2 - c + 13
z = 5c - 1
2(5c^3 + 2) - 3c*(6c^2 - c + 13) + 14c^3*(5c - 1) =
= 10c^3 + 4 - 3c*6c^2 + 3c*c - 39c + 70c^4 - 14c^3 =
= 10c^3 + 4 - 18c^3 + 3c^2 - 39c + 70c^4 - 14c^3 =
= 70c^4 - 22c^3 + 3c^2 - 39c + 4
Ответ:
Объяснение:
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5^(2x-3)-1≥0
5^(2x-3)≥1
2x-3≥0
2x≥3
x≥1,5
x∈[1,5;∞)
X^4-27x=0
X(x^3-27)=0
X=0 или X^3-27=0
X^3=27
X=3
Ответ: 0; 3