Y(3)=3/(3-2)=3/1=3
y`(x)=(1*(x-2)-x*1)/(x-2)²=(x-2-x)/(x-2)²=-2/(x-2)²
y`(3)=-2/(3-2)²=-2/1=-2
Y=3-2(x-3)=3-2x+6=9-2x
Х^2 + y^2 + 144 = ( X + y ) ^2 ;
X^2 + y^2 + 144 = x^2 + 2xy + y^2 ;
2xy = 144 ; xy = 72 ( то есть произведение этих чисел должно равняться 72 ) ;
А если это должны быть последовательеые нстуральные числа, то ОТВЕТ числа 8 и 9
Решение:
1) 40√3·√3/2·(-√2/2)=20·√3·√3·(-√2/2)=10·3·(-√2)=-30√2
2) 8√6 ·√2/2 ·(-√3/2)=4√6·√2·(-√3/2)=2√6·√2·(-√3)=-2√6·2·3=-2√36=-2·6=-12
3) 14√6 ·√3/2· (-√2/2)=7√6·√3·(-√2/2)=-7√18·(√2/2)
4) 28/(sin(-25π/4)cos(23π/4))=28/(-sin(6π+π/4)cos(5π+3π/4))=28/(-√2/2)·(1+(-√2/2))=14/(-√2/)·(1-√2/2)
5)23/(sin(-23π/6)cos(23π/3))=23/(sin(-3π+5π/6)cos(7π+2π/3))=23/(-1/2)(1-1/2)=23/(-1/4)=-23/4<span>
6)60/(sin(-32π/3)cos(35π/6))=60/(</span>sin(-10π +2π/3)cos(5π+5π/6))=60/(-√3/2)(1+(-√3/2))=-30√3·(1-√3/2)=-30√3+15·3=-30√3+45<span>
7)54/(sin(-28π/3)cos(23π/6))=</span>54/(-sin(9π)cos(5π+3π/6))=54/(0·cos(5π+3π/6)=54/0<span>
8)33√2cos(495°)=</span>33√2cos(360°+135°)=33√2cos(2π+3π/4)=33√2·(1-√2/2)=33√2-33√2·(√2/2)=33√2-33·2/2=33√2-33
(7-(m-3))(7+(m-3))=(7-m+3)(7+m-3)=(10-m)(4+m)
<span>{x²+y²-xy =16; x+y = -2 ⇔{(x+y)² -3xy =16 ; x+y = -2⇔{ (-2)² -3xy =16 ;
x+y =-2.<span>
{4 -3xy
=16 ;x+y = - 2 ⇔{x+y =-2 ; xy
= - 4.</span><span>
t² +2t -4
=0 ;
t ₁= -1-√5 ;</span><span>
t₂ =-1+√5.</span><span>
(x₁ = -1-√5 ; y₁ =- 1+√5 )</span><span>
(x₂= -1+√5 ; y₂=-1-√5)</span><span>
</span>ответ: { (-1-√5
; -1+√5) , (-1+√5 ; -1-√5) }<span>
****************************************
</span>можно было сразу поставить <span> y = -2 -x из второго уравнения в первое<span> :</span></span><span>
x²
+ -x-2) )² -x(-x-2) =16;
x²
+4+4x+x² +2x +x² =16 ;
3x² +
6x -12=0 ;
x²+2x -4
= 0.
</span><span>x₁ = -1-√5 ;</span><span>
x₂<span> = -1+√5.</span></span></span>
