<span>1) Р(х)=7х3-22х2+ах-1 Q(x) =х2-3х+1 </span><span>7(x^2 - 3x + 1)(x - q) = 7(x^3 - qx^2 - 3x^2 + 3xq + x - q)= </span><span>7(x^3 - (q + 3)x^2 + (3q + 1)x - q)= </span><span>7x^3 - 7(q + 3)x^2 + 7(3q + 1) x - 7q </span><span>q = 1/7 </span><span>a = 7(3q + 1) = 7(3/7 + 1) = 10 </span><span>2)Р(х) = 3х5-3х4+ах2-ах Q(х)=3х3+2 </span><span>(3х3+2)(x^2 + bx + c) = 3x^5 + 3bx^4 + 3cx^3 + 2x^2 + 2bx+2c </span><span>=> c = 0 </span><span>b = -1 </span><span>=> </span><span>a = 1</span>
И где задание, балбес?