3-х=2х;
3х=3;
х=1,тогда у=2•1=2; (1;2)-точка пересечения графиков
Решение
cosπ/12 - cos5π/12 = - 2*sin[(π/12 + 5π/12)/2]*sin[(π/12 - 5π/12)/2] =
= 2*sin(π/4)*sin(π/6) = 2*(√2/2)*(1/2) = √2/2
<span>12х+5 > 8х-5
</span>
<span>12х-8x> -5-5
</span>
<span>4x> -10
x>-10/4
</span>
<span>x>-2.5</span>
1) 6.22*4.7=29.234
2) 4.8076/4.04=1.19
3) 29.234-1.19=28.044
4) 28.044+1.956=30