√(-9 + 9x) - 3 = 0
ОДЗ: -9 + 9х ≥ 0 → 9х ≥ 9 → х ≥ 1
√(-9 + 9x) = 3
-9 + 9х = 9
9х = 18
х = 2
3p(8c+1)-8c(3p-5) = 24cp+3p-24cp+40c= <span>3p+40c
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</span><span>5n^2(3n+1)-2n(5n^2-3)= 15n^3+5n^2-10n^3+6n= 5n^3+5n^2+6n</span>
Решение
<span>х⁴-4х²-5=0
x</span>² = t > 0
t² - 4t - 5 = 0
t₁ = - 1 не удовлетворяет условию t > 0
t₂ = 5
x² = 5
x₁ = - √5
x₂ = √5