1.
2.
21√3 - 4√48 -√75=21√3 - 16√3 - 5√3=0
(5√2 -√18)*√2=5*2 - √36=10-6=4
3.
5.2х+3≥1.2x-13
2-3x>-1
5.2x-1.2x≥-13-3
-3x> -3
4x≥ -16
x<1
x≥ -4
x<1
-4≤x<1
[-4; 1)
Решим аналогичное уравнение:
__-__-6__+__0__-__14__+__
Ответ:
Sin(π/3 + a) = sin(π/3)cosa + cos(<span>π/3)sina
sin(</span>π/3 - a) = sin(π/3)cosa - cos(<span>π/3)sina
</span>sin(π/3 - a) - sin(π/3 + a) = sin(π/3)cosa - cos(π/3)sina - sin(π/3)cosa - cos(<span>π/3)sina =
</span>= -2cos(<span>π/3)sina = -2 * (1/2) sina = -sina</span>
Lg(9-2x-x^2) cos^2(x+1)≥<span>1
</span>lg((9-2x-x^2)^(cos^2(x+1))≥lg10
(9-2x-x^2)^(cos^2(x+1)≥10
x=-1