(a+5)²+(a-5)(a+5)+12=a²+10a+25+a²-25+12=2a²+10a-13
5x³-5(x-3)(9+3x+x²)=5x³-5x³-135=-135
<span>xy+2x+5y+10=x(y+2)+5(y+2)=(y+2)(x+5)
</span><span>3a²-6ax+3z², уверена что здесь нет ошибки?</span>
<span>1/2log_0.4(5*x+1)=log_0.4(x-1)
</span>√(5x + 1) = x - 1
ОДЗ: x - 1 > 0, x > 1
(√(5x + 1))^2 = (x - 1^2
5x + 1 = x^2 - 2x + 1
x^2 - 7x = 0
x(x - 7) = 0
x1 = 0
x2 = 7