Question

log(3) 6+log(3) 3/2 log(2) 15-log(2) 15/16

Answer 1

$log_{3}6+log_{3} \frac{3}{2}=log_{3} \frac{6*3}{2}=log_{3}9=2\\\\log_{2}15-log_{2} \frac{15}{16}=log_{2} \frac{15*16}{15}=log_{2}16=4$