Question

Решите уравнение x^2=-4x+32

Answer 1

${x}^{2} + 4x - 32 = 0 \\ d = 16 + 128 = 144 \\ x1 = \frac{ - 4 - 12}{2} = - 8 \\ x2 = \frac{ - 4 + 12}{2} = 4$

Ответ:-8,4.

Answer 2

x²=-4x+32

х²+4х-32=0

Д= 4²-4×1×(-32) = 16 + 128 = 144

х1 = -4 + 12 / 2 = 4

х2 = -4-12 / 2 =-8