1. а) 5 *5⁻²=5*1/5²=5*1\25=1/5=0.2
б) (1/2)⁻³=1⁻³/2⁻³=1/1/2³=8
в) (2⁻²)⁴*16²/2³=2⁻⁸*2⁸/2³=2⁰/2³=1/8
0,5а-2в+0,5а+0,1в=1а-1,9в
![x^3+5x^2-6x-2\ \textless \ 3x^2-3x+4 \\ x^3+2x^2-3x-6\ \textless \ 0 \\ x^2(x+2)-3(x+2)\ \textless \ 0 \\ (x+2)(x^2-3)\ \textless \ 0 \\ (x+2)(x- \sqrt{3})(x+ \sqrt{3})\ \textless \ 0](https://tex.z-dn.net/?f=x%5E3%2B5x%5E2-6x-2%5C%20%5Ctextless%20%5C%203x%5E2-3x%2B4%20%5C%5C%20x%5E3%2B2x%5E2-3x-6%5C%20%5Ctextless%20%5C%200%20%5C%5C%20x%5E2%28x%2B2%29-3%28x%2B2%29%5C%20%5Ctextless%20%5C%200%20%5C%5C%20%28x%2B2%29%28x%5E2-3%29%5C%20%5Ctextless%20%5C%200%20%5C%5C%20%28x%2B2%29%28x-%20%5Csqrt%7B3%7D%29%28x%2B%20%5Csqrt%7B3%7D%29%5C%20%5Ctextless%20%5C%200%20%20)
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_______-_______-2______+_____-√3________-_______√3_____+_____
x∈(-∞;-2)U(-√3;√3)
Ответ: x∈(-∞;-2)U(-√3;√3)