( ⁴ √ 24 + ⁴ √ 6 ) ² : ( 4√3 + 3 √ 6 )
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1) ( ⁴ √ 24 + ⁴ √ 6 ) ² = ( ⁴√24 )² + ( ⁴√6 )² + 2 *( ⁴√24 )*( ⁴√ 6 ) = ( √ 24 ) + ( √ 6 ) +
+ 2( ⁴√ ( 24 * 6 ) = 3 √ 6 + 2 ( ⁴ √ 144 ) = 3 √ 6 + 2 * √ 12 = 3 √ 6 + 4 √ 3
2) ( 3 √ 6 + 4 √ 3 ) : ( 4 √ 3 + 3 √ 6 ) = 1
Ответ 1
A) 2a²b²-6ab²+2a²b=
=2ab(ab-3b+a)
3kx+k²x²-9kx=0
k²x²-6kx=0
kx(kx-6)=0
kx=0⇒x=0 U k∈R
kx=6⇒x=6/k,k≠0
Ответ k∈(-∞;0) U (0;∞)