sin(x+pi/12)cos(x-pi/12)=1/2
2sin(x+pi/12)cos(x-pi/12)=1
SIN(2x+pi/6)=1
2x+pi/6=pi/2+2pi n
2x=pi/3+2pi n
x=pi/6+pi n,neZ
д
3*1^2-a=0
3-a=0
a=3
вот так)
2x^2 + 11x + 34 = (x+6)^2
2x^2 +11x +34 = x^2 + 12x + 36
x^2 - x - 2 = 0
D = 1+ 8 = 9
x1 = (1+ 3)/2 = 2
x2 = (1-3)/2 = -1
Ответ: 2 и -1