B6=b1*g^5;
b3=b1*g^2;
b6 : b3=(b1*g^5) / (b1*g^2) =g^3;
g^3= - 5 / -40 ;
g^3= 1/8 ;
g^3 = (1/2)^3 ;
g= 1/2
-x-15,4=-5,4+3,7-2x
-x+2x=15,4-5,4+3,7
x=13,7
1 + tga / 1 + ctga= (1+sina/cosa)/(1+cosa/sina)=
=((cosa+sina)/cosa)/(cosa(sina+cosa) = sina/cosa=tga
<span>2x^2 + 3x - 5 = 0
D = b2 - 4ac
D = 9 + 40 = 49 = 7^2</span><span>x1,2 = -b ± √D/2a
x1 = -3 + 7/4 = 4/4 = 1
x2 = -3 - 7/4 = - 10/4 = - 5/2
Ответ: x1 = 1 ; x2 = - 5/2</span>