![-1 \leq cos(\alpha) \leq 1](https://tex.z-dn.net/?f=-1+%5Cleq+cos%28%5Calpha%29+%5Cleq+1)
- возможные значения косинуса
![2cos^2(x) - 5cos(x) + 3 = 0\\\\ 2cos^2(x) - 2cos(x)-3cos(x) + 3 = 0\\\\ 2cos(x)*(cos(x) - 1)-3*(cos(x) -1) = 0\\\\ (2cos(x) - 3)*(cos(x) -1) = 0\\\\ 2cos(x)-3=0\ \ or\ \ cos(x)-1=0\\\\ cos(x)=\frac{3}{2}\ \ or\ \ cos(x)=1\\\\ cos(x)=1\\\\ x=2\pi n,\ n\in Z](https://tex.z-dn.net/?f=2cos%5E2%28x%29+-+5cos%28x%29+%2B+3+%3D+0%5C%5C%5C%5C%0A2cos%5E2%28x%29+-+2cos%28x%29-3cos%28x%29+%2B+3+%3D+0%5C%5C%5C%5C%0A2cos%28x%29%2A%28cos%28x%29+-+1%29-3%2A%28cos%28x%29+-1%29+%3D+0%5C%5C%5C%5C%0A%282cos%28x%29+-+3%29%2A%28cos%28x%29+-1%29+%3D+0%5C%5C%5C%5C%0A2cos%28x%29-3%3D0%5C+%5C+or%5C+%5C+cos%28x%29-1%3D0%5C%5C%5C%5C%0Acos%28x%29%3D%5Cfrac%7B3%7D%7B2%7D%5C+%5C+or%5C+%5C+cos%28x%29%3D1%5C%5C%5C%5C%0Acos%28x%29%3D1%5C%5C%5C%5C%0Ax%3D2%5Cpi+n%2C%5C+n%5Cin+Z)
Ответ:
![2\pi n,\ n\in Z](https://tex.z-dn.net/?f=2%5Cpi+n%2C%5C+n%5Cin+Z)
Ответ: 98*t+790*q - потратил Миша ; 21*t+1990*q- потратил Олег. получаем: 98*t+790*q+21*t+1990*q=119*t+2780*q (рублей). Ответ: 119*t+2790*q (рублей). Ответ: 119*t+2780*q, а не 2790.
Объяснение:
1)2x+3y-(5x-y)=x+2y-(2x+3y)
2x+3y-5x+y=x+2y-2x-3y
2x-5x-x+2x=2y-3y-3y-y
-2x=-5y
x=2,5y
2)(xy+1)/(y+1)²=(x-1)²/(xy+1)
(2,5y²+1)/((y+1)²=(2,5y-1)²/(2,5y²+1)
6,25y^4 +5y²+1=6,25y^4-5y³+y²+12,5y³-10y²+2y+6,25y²-5y+1
7,5y³-7,75y²-3y=0
y(7,5y²-7,75y-3)=0
y=0 -не удов усл
7,5y²-7,75y-3=0
D=60,0625+90=150,0625 √D=12,25
y1=(7,75-12,25)/15=-0,3⇒x1=2,5*(-0,3)=-0,75
y2=(7,75+12,25)/15=4/3⇒x2=5/2*4/3=10/3
(-0,75;-0,3) U (10/3;4/3)
1). 27³-729+81²=19683-729+6561=25515:35=729
Да, делится на 35
2). (x-2)(x-6)-2(x-3)-18=0
x²-6x-2x+12-2x+6-18=0
x²-10x=0
x(x-10)=0
x=0 x-10=0
x=10
1)2*(х-4)=3 2)7*(-3+2х)=-6х-1
2х-8=3 -21+14х=-6х-1
2х=3+8 14х+6х=-1+21
2х=11 20х=20
х=11:2 х=20:20
х=5,5 х=1