Question

Выполните действия :1)(4x^2)^3; 2)(-2a^4b^2)3; 3)0,3v^2×(-1/3u^4×v^6); 4)(1/4x^2y)^3×(-32x^2×b)

Answer 1

$(4x^2)^3=64x^6 \\ \\ (-2a^4b^2)^3=-8a^{12}b^{6}\\\\ 0,3v^2*(- \frac{1}{3} u^4*v^6)= \frac{3}{10}v^2(- \frac{1}{3} u^4v^6) =- \frac{1}{10} u^4v^8 \\\\ ( \frac{1}{4} x^2y)^3*(-32x^2*b)=( \frac{1}{64} x^6y^3)(-32x^2b)=- \frac{1}{2}bx^8y^3$