f(x) = (x² - 2x - 3)²
f'(x) = 2(x² - 2x - 3)(2x - 2) = 4(x² - 2x - 3)(x - 1) = 4(x - 3)(x + 1)(x - 1)
f'(x) = 0 => 4(x - 3)(x + 1)(x - 1) = 0
x - 3 = 0 => x = 3
x + 1 = 0 => x = -1
x - 1 = 0 => x = 1
Ответ: x = 3, x = 1, x = -1.
В1=3*1=3
В2=3*2=6
g=6/3=2
S6=3(2(в степени 6) -1)/(дробь)2-1=3*63/1=189(б)