Question

(√8 -3)(3+2√2) Помогите решить пример

Answer 1

$(\sqrt8-3)(3+2\sqrt2)=3\sqrt8-9+2\sqrt2\bullet\sqrt8-6\sqrt2=\\\\=3\sqrt{2^2\bullet2}-9+2\sqrt{2\bullet8}-6\sqrt2=3\bullet2\sqrt2-9+2\sqrt{16}-6\sqrt2=\\\\=6\sqrt2-9+2\bullet4-6\sqrt2=-9+8=-1.$