Смотри ответ в приложении
2x^2-10x = 0
2x(x - 5) = 0
1) 2x = 0
x = 0
2) x - 5 = 0
x = 5
<span>1
(1+sin2h)/cos2h=tg(pi/4+h)</span><span>
(1+sin2h)/cos2h=(cosh</span>²+sin²h+2sinhcosh)/(cos²h-sin²h)=
=(cosh+sinh)²/(cosh-sinh)(cosh+sinh)=<span>(cosh+sinh)/(cosh-sinh)
tg(</span>π/4+h)=sin(π/4+h)cos(π/4+h)=(sinπ/4cosh+cosπ/4sinh)/(cosπ/4cosh-sinπ/4sinh)=√2/2(cosh+sinh)/√2/2(cosh-sinh)=<span>(cosh+sinh)/(cosh-sinh)
</span>(cosh+sinh)/(cosh-sinh)=<span>(cosh+sinh)/(cosh-sinh)</span>