1) y'=(3x+x^3)' (x-2) + (3x+x^3) (x-2)' = (3+3x^2)(2-x)+ 3x + x^3 = 6 -3x + 6x^2 - 3x^3 + 3x + x^3 = - 2x^3 + 6x^2 + 6
(m^(-6))^(-2)*m^(-14)=m^(-14)/m^(-12)=m^12/m^14=m^(-2)=1/m^2
1) а(b-c)
2) m(n-1)
3) 3(3x-y)
4) 1.5(3+n)
5) mn(k-1)
6) a(bc+n)