Question

Решите уравнение (х+у-1)²+(2х-у-8)²=0

Answer 1

${(x + y - 1)}^{2} = - {(2x - y - 8)}^{2} \\ \\ x + y - 1 = 0 \\ 2x - y - 8 = 0 \\ \\ y = 1 - x \\ y = 2x - 8 \\ \\ 1 - x = 2x - 8 \\ x = 3 \\ y = 1 - 3 = - 2$

Ответ: (3;-2)