2cos x*sin x - sin^2 x - 2sin x - 2cos x + sin x + 2 = cos^2 x
2cos x*sin x - sin x - 2cos x + 2 = cos^2 x + sin^2 x = 1
2cos x*sin x - 2cos x - sin x + 1 = 0
2cos x*(sin x - 1) - (sin x - 1) = 0
(2cos x - 1)(sin x - 1) = 0
1) cos x = 1/2; x1 = +- pi/3 + 2pi*k
2) sin x = 1; x2 = pi/2 + 2pi*k
Arccos(ctg3π/4)=?
ctg3π/4=ctg(π-π/4)=ctgπ/4=1
arccos1=0°;(cos0°=1)
X^2 - 3x - 4>0
a=1, b=3, c=4
Д = b^2 - 4ac= (-3)^2 - 4•1•(-4) = 9+16 = 25= 5^2
x1 = 3+5/2= 4
x2 = 3-5/2= -1
(x^2- это значит x в квадрате и тд)