Question

Помогите решить уравнение

Answer 1

$(2x-5)(2x-5)=(2x-3)(2x+3)$

$4x^{2}-10x-10x+25= 4x^{2}+6x-6x-9$

$4x^{2}-20x+25-4x^{2}+9=0$

$-20x+34=0$

$-20x=-34$

$x=1,7$

Answer 2

(2x - 5)^2 = 4x^2 - 9 
4x^2 - 20x + 25 = 4x^2 - 9 
4x^2 - 20x + 25 - 4x^2 + 9 = 0 
- 20x + 34 = 0 
- 20x = - 34
x = 34/20 
x = 1,7