Sin(x+pi/6)≤√3/2
pi/3+2pi n≤x+pi/6≤pi/2+2pi n , где n∈Z
pi/6+2pi n≤x≤pi/3+2pi n
<span>4x(y²-9)+4x²(y²-9)-9+y²=</span><span>4x(y²-9)+4x²(y²-9)+(y²-9)=</span>
(y²-9)(4x²+4x+1)=(y-3)(y+3)(2x+1)(2x+1)<span>
</span>
10*1/(16-1^2)+5/(1-4)=10/(16-1)+5/(1-4)=10/15+5/(1-4)=(2/3)+5/(1-4)=(2/3)+5/(-3)=(2/3)+(-5/3)=(2/3)+(-(5/3))=-1