Question

Номер 5555555555555555
и желательно 666666666666

Answer 1

I hope this helps you

Answer 2

$\frac{v-8}{3}= \frac{5-4v}{5} + \frac{6v}{4}$  |*60
$20(v-8)=12(5-4v)+15*6v$
$20v-160=60-48v+90v$
$22v=-220$
$v=-10$

$8v(v-w+x)+8w(v+w-x)-8x(v-w-x)=$$8v^{2}-8vw+8vx+8vw+8w^{2}-8wx-8vx+8xw+8x^{2}=$$8v^{2}+8w^{2}+8x^{2}=8(v^{2}+w^{2}+x^{2})$