X≠0, y≠0
x-y=6
x=6+y
(6+y)/y + y/(6+y) = 10/3
((6+y)²+y²) / y(6+y) = 10/3
3((6+y)²+y²) = 10y(6+y)
108+36y+6y² = 60y+10y²
4y²+24y-108=0
y²+6y-27=0
D=36-4*(-27)=36+108=144=12²
y1=(-6+12)/2=6/2=3
y2=(-6-12)/2=-18/2=-9
x1=6+3=9
x2=6+(-9)=6-9=-3
ответ: (9;3) (-3;-9)
5)(aˇ3-bˇ3)/a(a-b)=(a-b)(aˇ2+ab+bˇ2)/a.(a-b)=(aˇ2+ab+bˇ2)/a
6)zadanie ploxo bidno
7)(aˇ3+1).(a-1)/(aˇ2-a+1)=(a+1)(aˇ2-a+1)(a-1)/(aˇ2-a+1)=
=(a+1)(a-1)=aˇ2-1
8)(bˇ2-1)(bˇ2+b+1)/(bˇ3-1)=(b+1)(b-1)(bˇ2+b+1)/(b-1)(bˇ2+b+1)=b+1