<span>(2-x^2)^4-10(2-x^2)^2=-9
2 - x</span>² = z
z⁴ - 10z² + 9 = 0
z² = t
t² - 10t + 9 = 0
t₁ = 1
t₂ = 9
z² = 1
z₁ = - 1
z₂ = 1
z² = 9
z₃ = - 3
z₄ = 3
2 - x² = - 1
x² = 3
x₁ = - √3
x₂ = √3
2 - x² = 1
x² = 1
x₃ = - 1
x₄ = 1
2 - x² = - 3
x² = 5
x₅ = -√5
x₆ = √5
2 - x² = 3
x² = - 1 нет решения
Пусть х лет-папе, тогда 2х-дедушке.
Вариант 1
1. а) =(4-x)² /(x-4) =(x-4)²/(x-4) =x -4
b) =x²(x^3 -3) /2x^4(x^3 -3) =1/2x²
в) x^4 -2x²y² +y^4 =(x² -y²)² =(x²-y²)(x²-y²) =(x-y)(x+y)(x-y)(x+y) =(x-y)²(x+y)²
=7y²(x²-2xy+y²) /(x-y)²(x+y)² =7y²(x -y)² /(x-y)²(x+y)² =7y² /(x+y)²
вариант 2
1. а) =(5-x)² /(x-5) =(x-5)² /(x-5) =x -5
b) =x²(3x²+2) /5x^6(3x²+2) =1/5x^4
в) =(x²-y²)² / (12x^3y +12x²y²) =(x-y)²(x+y)² / 12x²y(x+y)=(x+y)(x-y)² /12x²y
9x-11>10x-15
c X в одну сторону, с чилами в другую
x<4