ну...log2(log3 2.25+log3 log2 16)=log2(log3 2.25+log3 4)=log2(log3 9)=log2 2=1
Решение
х+17/5 ≤ .х-5/4
2x ≤ - 1,25 - 3,4
2x ≤ - 4,65
x ≤ - 4,65 / 2
x ≤ - 2,325
x ∈ (- ∞; - 2,325]