tg(-13π/3+4π)=tg(-π/3)=-tg(π/3)=-√3/3
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Y=x³-4x²+2x y=1-2x
x³-4x²+2x=1-2x
x³-4x²+4x-1=0
(x³-1)-(4x²-4x)=0
(x-1)(x²+x+1)-4x*(x-1)=0
(x-1)(x²+x+1-4x)=0
x-1=0
x₁=1
x²-3x+1=0 D=5
x₂=(3+√5)/2 x₃=(3-√5)/2
Ответ: x₁=1 x₂=(3+√5)/2 x₃=(3-√5)/2.