<span>Найдите три решения уравнения 7x+2y=3
1) x=0 y=3/2
2) x=1 y=(3-7)/2 =-2 x=1 y=-2
3) x=2 y= (3-14)/2=-11/2 </span><span>x=2</span> y=-11/2
sin(x/2- π/6)+1=0
1 = sin(π/2)
sin(x/2 - π/6) + sin(π/2) = 0
sin(x/2 - π/6) = -sin(π/2)
sin(x/2 - π/6) = sin(-π/2)
x/2 - π/6 = (3x - π)/6
(3x - π)/6 = -π/2
3x - π + 3π = 0
3x +2π = 0
3x = -2π
x = -2π/3
Ответ: -2π/3
1) 17+8=25
2)38-(-1)=39
3)48:(-16)=-3
4)-3•(-13)=39
5)0.5:4=0.125
6)-3:1/3=-9
<span>Вынесем минус за скобку и увидим формулу квадрата разности:
- 9a</span>⁴<span> + 24 а</span>²<span>b</span>²<span> - 16 b</span>⁴ =
= - (9a⁴ - 24a²b² + 16b⁴) =
= - ((3a²)² - 2*3a²*4b² + (4b²)²) =
= - (3a² - 4b²)² =
= - (3a² - 4b²)(3a² - 4b²) =
= (3a² - 4b²)(4b² - 3a²)