<span>2sin^4x+3(cos^2x-sin^2x)+1=0 2sin^4x+3(1-sin^2x-sin^2x)+1=0 2sin^4x+3-6sin^2x+1=0 2sin^4x-6sin^2x+4=0 sin^2x=y</span>
<u>Ответ: область значений функции промежуток [3;7].</u>
( X - 4)*( X - 5 ) - 2X * ( X - 6 ) = X^2 - 5X - 4X + 20 - 2X^2 + 12X =
= - X^2 + 3X + 20
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7Y * ( X + Y - P ) - 7P * ( X - Y - P ) + 7X * ( X - Y + P ) =
= 7XY + 7Y^2 - 7YP - 7XP + 7YP + 7P^2 + 7X^2 - 7XY + 7XP =
= 7X^2 + 7Y^2 + 7P^2
2х^2-3х+1=0
D=b^2-4ac= (-3)^2-4*2*1=9-8=1
x1=3+1/4= 4/4=1
x2=3-1/4=2/4=0,5