Log5(25-x)= 3
log5(25-x)= log5 125
сокращаем логарифмы
и получаем уравнение
25-х=125
х=-100
ответ: х=-100
1
а)sin(2π+π/6)=sinπ/6=1/2
б)-tg(2π-π/6)=tgπ/6=√3/3
в)cosπ+ctg(π+π/3)=-1+√3/3
г)tgπ/4*(-ctgπ/4)+cos3π/2*sinπ/2=-1+0*1=-1
д)sin(360+45)+cos(180+45)*tg(180+45)=sin45-cos45*tg45=√2/2-√2/2*1=0
2
sin²t+cos²t/(ctgt*tgt)=sin²t+cos²t=1
3
1)cost=1/2
t=+-π/3+2πn,n∈z
2)cos(π/2+t)=-√3/2
-sint=-√3/2
sint=√3/2
t=(-1)^n*π/3+πn,n∈z
4
cost=-4/5
sint=-√(1-cos²t)=-√(1-16/25)=-√(9/25)=-3/5
tgt=sint/cost=-3/5:(-4/5)=3/5*5/4=3/4
ctgt=1/tgt=1:3/4=4/3
10х-1,76=1,1-1,76+5х
10х-5х=1,1-1,76+1,76
5х=1,1
Х=0,22
1) ( a^3 - 1) + (a^2 - a) = (a - 1)(a^2 + a + 1) + a(a - 1) = (a - 1)(a^2+a+1+a)=
= ( a - 1)(a^2 + 2a + 1)
2) (2x^3 - 2xy^2) - 8( x^2 - y^2) = 2x( x^2 - y^2) - 8(x^2 - y^2) =
= ( x^2 - y^2)(2x - 8) = 2(x + y)(x - y)(x - 4)
3) (5a^2 - 5b^2) - 15ab(a^2 - b^2) = 5(a^2 - b^2) - 15ab(a^2 - b^2) =
= (a^2 - b^2)( 5 - 15ab) = 5(a- b)(a + b)( 1 - 3ab)
4) (a^2b^2 - b^2) + (a^2 - 1) = b^2(a^2 - 1) + (a^2 - 1) = (a^2 - 1)(b^2 +1)=
= (a - 1)(a+ 1)(b^2 + 1)
Успехов!)))