<em>Ответ: во вложении объяснение:</em>
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Решение задания смотри на фотографии
2) (x²+4y²)/(x-2y)+4xy/(2y-x)=(x²+4y²)/(x-2y)-4xy/(x-2y)=(x²-4xy+4y²)/(x-2y)= =(x-2y)²/(x-2y)=<span>x-2y;
4) (9a</span>²+4y²)/(3a-2y)+12ay/(2y-3a)=(9a²+4y²)/(3a-2y)-12ay/(3a-2y)=(9a²-2ay+4y²)/(3a-2y)=(3a-2y)²/(3a-2y)=<span>(3a-2y)$
6) (a</span>²x²+25y²)/(ax-5y)+10axy/(5y-ax)= (a²x²+25y²)/(ax-5y)-10axy/(ax-5y)= =(a²x²-10axy+25y²)/(ax-5y)=(ax-5y)²/(ax-5y)=<span>(ax-5y)</span>
3х+х=340
х=340/4
х=85
3х=85*3=255
8.7 - (2m - 1/3 m) + (n + 2/3 n) = 8.7 - 1.2/3 m + 1. 2/3n